In the group of 23 people the possibility that 2 people have birthday in the same day is about 50%.
First lets count the possibility for the variable group of people.(N-is the number of people in the group)
Let's take one person and remember his birthday. Then let's take second person. The possibility that his birthday won't match with the first person's birthday is (1-(1/365))=364/365.Then let's take third person. the possibility that his birthday won't match the previous two is ((1-(2/365)=363/365. Then the forth....is ((1-(3/365)....The Nth will have ((1-((n-1)/365))=(366-n)/365. So if we multiply all these possibilities we will get that the possibility that all N members of the group have different birthday is
t=(364*363*362*361....(366-n))/(365^n)
[365^n is the equivalent of writing 365 to the power of N)
So the possibility that at least 2 people have birthday on the same day is 1-t
If you count it for t=23 you will see that 1-t is slightly above 50%.
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